maths. question?

2016-09-06 11:18 am
evaluate (6 ^ -2/3^ -5)^3 ÷(16/81)^ -2
更新1:

use law of integral indices!!!

回答 (2)

2016-09-14 4:03 pm
(6 ^ -2/3^ -5)^3 ÷(16/81)^ -2
=(27/4)^3÷(6561/256)
=(19683/64)÷(6561/256)
=12
2016-09-08 3:36 am
0


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