the forumla is propane is C3H8 and butane is C4H10 than why in chloropropane the formula is CH3-CH2-CH2-Cl in which there is 7 hydrogen only?

2016-09-03 5:49 pm
and in 1-cholorobutane the formula is CH3-CH2-CH2-CH2-Cl in which 9 hydrogen is present?
更新1:

i am talking about the HYDROGEN there should be 8 hydrogen due to C3H3 but instead chlorobutane have 5 hydrogen and there should be 10 hydrogen due the formula of C4H10 but there are 9 hydrogen present instead of 10

更新2:

i meant C3H8 not C3H3

回答 (2)

2016-09-03 6:49 pm
✔ 最佳答案
The naming of organic compounds is based on the number od C atoms in the molecule.
Propane has 3C atoms in its molecule (+ 8H atoms)
Butane has 4C atoms in its molecule (+10H atoms )
If you substitute a Cl atom for an H atom , this does not change the naming system
Chloropropane has 3 C atoms in its molecule ( + 7H atoms + 1 Cl atom)
Chlorobutane has 4 C atoms in its molecule ( + 9 H atoms + 1 Cl atom)
Organic chemistry and its naming are based on carbon - not hydrogen
2016-09-03 5:58 pm
The chloroalkanes are formed by substituting a chlorine atom for a hydrogen. The carbon atoms in both the starting material and products contain the maximum bonds they are able to form. (Four)


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