tig. problem help needed!?
2016-09-03 7:05 am
A triangle has sides of lengths 2.00 m, 3.00 m, and x. The corresponding sides of a similar triangle have lengths 4.20 m, y, and 9.03 m. Determine the values of x and y.
回答 (4)
2016-09-03 7:10 am
The first number of each determines the ratio 2.00 to 4.20
y = 3.00m (4.20/2.00) = 6.30m
x = 9.03 (2.00/4.20) = 4.30m
y = 3.00m (4.20/2.00) = 6.30m
x = 9.03 (2.00/4.20) = 4.30m
2016-09-03 9:18 am
4.20/2.00=2.10
y=3.00*2.10= 6.30 m
x=9.03/2.10= 4.30 m
y=3.00*2.10= 6.30 m
x=9.03/2.10= 4.30 m
2016-09-03 7:32 am
2/4.2 = 3/y = x/9.03
2/4.2 = 3/y
y = 3*4.2/2 = 6.3 m
2/4.2 = x/9.03
x = 9.03*2/4.2 = 4.3 m
2/4.2 = 3/y
y = 3*4.2/2 = 6.3 m
2/4.2 = x/9.03
x = 9.03*2/4.2 = 4.3 m
2016-09-03 7:11 am
The ratio of the sides of the second triangle to those of the first are apparently
.. 4.20/2.00 = y/3.00 = 9.03/x
Then
.. y = 2.10*3.00 = 6.30
.. x = 9.03/2.10 = 4.30
.. 4.20/2.00 = y/3.00 = 9.03/x
Then
.. y = 2.10*3.00 = 6.30
.. x = 9.03/2.10 = 4.30
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https://hk.answers.yahoo.com/question/index?qid=20160902230537AAx1huN