2(x-1)平方-7=91 ,點計?
回答 (2)
Sol
2(x-1)^2-7=91
2(x-)^2=98
(x-)^2=49
x-1=7 or x-1=-7
x=8 or x=-6
2[(x-1)^2]-7=91
2[(x^2)-x+1]-7=91
2(x^2)-2x+2-7=91
2(x^2)-2x-96=0
x={-(-2)±√{[(-2)^2]-4(2)(-96)}}/[2(2)]
=[2±√(4+768)]/4
={2[1±√(193)]}/4
=[1±√(193)]/2
收錄日期: 2021-04-18 15:29:02
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