What is the least common denominator of 1/((X^2)-4) 1/(4X-8)?

👨🏻‍🏫 學術台數學

[匿名]

2016-08-23 2:47 pm

更新1:

What is the least common denominator of 1/((X^2)-4) + 1/(4X-8)?

回答 (3)

2016-08-23 2:49 pm

✔ 最佳答案

The denominators are

x^2 - 4 = (x-2)(x+2)

and

4x - 8 = 4(x-2)

so the least common denominator is

4(x-2)(x+2)

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DWRead

2016-08-23 5:08 pm

1/(x²-4) = 1/((x+2)(x-2)
1/(4x-8) = 1/(4(x-2))
LCD = 4(x-2)(x+2) = 4x²-16

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lenpol7

2016-08-23 4:33 pm

Factor
1/(x - 2)(x + 2) & 1/(4(x - 2))

LCM is4(x - 2)

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