(9*9*9*9*9*9)*(-531441)*(-14348907)=3的A次方=9的B次方 請問A+B是多少 若可以最好附上算式 謝謝~?
回答 (1)
2016-08-21 9:24 am
Sol
531441=3^12
14348907=3^15
(9*9*9*9*9*9)*(-531441)*(-14348907)
=(9*9*9*9*9*9)*(531441)*(14348907)
=(3^12)*(3^12)*(3^15)
=3^(12+12+15)
=3^39
=9^19.5
A+B=39+19.5=58.5
531441=3^12
14348907=3^15
(9*9*9*9*9*9)*(-531441)*(-14348907)
=(9*9*9*9*9*9)*(531441)*(14348907)
=(3^12)*(3^12)*(3^15)
=3^(12+12+15)
=3^39
=9^19.5
A+B=39+19.5=58.5
收錄日期: 2021-04-30 21:42:13
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20160821005616AA9yhKS