math question.............?

2016-08-18 3:19 pm
line 1 is defined by slope m=1/2 and y intercept c is =2. Line 2 passes through the points (x1,y1)= (-4,1)
and (x2,y2)=4,-15).

are the lines perpendicular, parallel or neither?

thank you.

回答 (3)

2016-08-18 3:22 pm
The slope of the first line is given at 1/2.

If the two lines are perpendicular, then line 2 will have a slope of -2 (opposite-reciprocal).
If the two lines are parallel, then line 2 will have a slepe of 1/2 (same slopes)
And if anything else, it's neither.

For line 2, we are given two points, so we can calculate the slope by finding the differences in y's and x's and dividing them:

change in y / change in x
(1 - (-15)) / (-4 - 4)
16 / (-8)
-2

Since the slope is -2, the two lines are perpendicular.
2016-08-18 5:49 pm
(1 - (-15))/(-4 - 4) = 16/-8 = -2.

Above is how to get the gradient/slope of line 2 given two points. For two lines to be parallel, their slopes must be the same with different y-intercepts. You don't have that here. Perpendicular lines have slopes that are negative reciprocals; i.e., their product is -1. The slopes are 1/2 (given) and -2 (see work above)...their product is -1.

These lines are therefore PERPENDICULAR.
2016-08-18 4:03 pm
m2 = -2 so the lines are perpendicular. Perpendicular lines have opposite reciprocal slopes


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