A ball is thrown straight up. The distance s of the ball from the ground is given by the functions s(t)=240+32t-4t^2?
Find the maximum height attained by the ball.
回答 (4)
s ` (t) = 32 - 8t = 0 for turning point
t = 4
s (4) = 240 + 128 - 64
s (4) = 304 _______max. height
s = 240 + 32t - 4t^2
ds/dt = 32 - 4 * 2t = 0 when the ball reaches to highest point.
32 = 8t
t = 4
s = 240 + 32*4 - 4*4^2
= 240 + 128 - 64
= 304
without UNITS this is a MATH question not a PHYSICS question per se :>)
收錄日期: 2021-04-21 19:33:05
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