{3^(x+y) = 27 { (log(y)/(log(2x+9))) - 1 = 0 Solve for x and y?

{ 3^(x + y) = 27
{ log(y)/log(2x + 9) - 1 = 0

{ 3^(x + y) = 3^3
{ log(y)/log(2x + 9) = 1

{ x + y = 3
{ log(y) = log(2x + 9)

{ x + y = 3
{ y = 2x + 9

x + (2x + 9) = 3
3x = -6
x = -2
y = 3 - x = 3 - (-2) = 5

{ x = -2
{ y = 5

3^(x+y)=27
x+y=3 i
(log(y)/(log(2x+9))) - 1 = 0
log y=log(2x+9)
y=2x+9
2x-y=-9 ii
x=-2
y=5