{4^(x+y)=2 {4^(x-y) = 16 solve for x and y?

[匿名]

2016-08-09 3:19 am

回答 (1)

蓁奇

2016-08-10 11:33 am

4^（x+y)= 2^2(x+y)= 2= 2^1
16=4^2 =4^(x-y)
2(x+y)=1,x+y=1/2
x-y=2
x=5/4,y=-3/4

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