{4^(x+y)=2 {4^(x-y) = 16 solve for x and y?
回答 (1)
2016-08-10 11:33 am
4^（x+y)= 2^2(x+y)= 2= 2^1
16=4^2 =4^(x-y)
2(x+y)=1,x+y=1/2
x-y=2
x=5/4,y=-3/4
16=4^2 =4^(x-y)
2(x+y)=1,x+y=1/2
x-y=2
x=5/4,y=-3/4
收錄日期: 2021-04-20 16:27:11
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20160808191932AAvN3LW