更新1:
please show steps, i want to understand .
Calculate the concentration of all ions present in 0.262 g AlCl3 in 250.0 mL of solution. __M Al3+ __M Cl-?
回答 (3)
2016-08-08 5:48 am
✔ 最佳答案
AlCl3 → Al{3+} + 3 Cl{-}(0.262 g AlCl3) / (133.3405 g AlCl3/mol) x (1 mol Al{3+} / 1 mol AlCl3) / (0.2500 L) = 0.00786 mol/L =
0.00786 M Al{3+}
(0.00786 mol/L Al{3+}) x (3 mol Cl{-} / 1 mol Al{3+}) = 0.0236 mol/L = 0.0236 M Cl{-}
2016-09-20 10:12 pm
thanks for all the answers!
2016-09-19 2:42 am
It's a very interesting question, looking forward to going through the replies
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原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20160807205107AA5lFRH