如 tan = 3分之二 求3 cos-2 sin分之2 sin+3 cos 的值?

tan x=2/3
(2 sin x+3 cos x)/(3 cos x -2 sin x)
=[(2 sin x+3 cos x)(1/cos x)]/[(3 cos x -2 sin x)(1/cos x)]
=(2 tan x+3)/(3-2 tan x)
=(2*2/3 +3)/(3-2*2/3)
=2.6
=13/5

(2 sin+3 cos )/(3 cos-2 sin)
=(2tan +3)/(3- 2tan)
=(4/3 +3)/(3-4/3)
=(4+9)/(9-4)
=13/5