各位大大 幫忙我因式分解一下好嗎 x^2-2xy+y^2+2x-2y-8 謝謝?????????????

x² - 2xy + y² + 2x - 2y - 8
= (x - y)² + 2(x - y) - 8
= (x - y + 4)(x - y - 2)

註：
z² + 2z - 8 = (z + 4)(z - 2)

(x-y)(x-y+2)-8

x^2-2xy+y^2+2x-2y-8
=(x-y)^2+2(x-y)-8
=[(x-y)-2][(x-y)+4]
=(x-y-2)(x-y+4)