各位大大 幫忙我因式分解一下好嗎 x^2-2xy+y^2+2x-2y-8 謝謝?????????????
回答 (3)
2016-08-06 4:43 am
✔ 最佳答案
x² - 2xy + y² + 2x - 2y - 8 = (x - y)² + 2(x - y) - 8
= (x - y + 4)(x - y - 2)
註：
z² + 2z - 8 = (z + 4)(z - 2)
2016-10-13 1:10 am
(x-y)(x-y+2)-8
2016-08-06 4:02 pm
x^2-2xy+y^2+2x-2y-8
=(x-y)^2+2(x-y)-8
=[(x-y)-2][(x-y)+4]
=(x-y-2)(x-y+4)
=(x-y)^2+2(x-y)-8
=[(x-y)-2][(x-y)+4]
=(x-y-2)(x-y+4)
收錄日期: 2021-04-18 15:27:09
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20160805195254AA45T85