Chemistry help???!!?

2016-08-05 3:19 am

1. Write the equilibrium expressions for the following reactions:
a) 2 N2O(g) + O2(g) ←→ 4 NO(g)

b) H2(g) + CO2(g) ←→ H2O(g) + CO(g)

c) 4 HCl(g) + O2(g) ←→ 2 Cl2(g) + 2 H2O(g)

d) 3 H2(g) + N2(g) ←→ 2 NH3(g)

e) H2(g) + Cl2(g) ←→ 2HCl(g)

f) 2 SO2(g) + O2(g) ←→ 2 SO3(g)

2. Using the above equilibrium expressions, calculate the equilibrium constant, K, for the following concentrations:
a) [N2O] = 0.0035 M, [O2] = 0.0027 M, [NO] = 5.6 x 10-9 M

b) [H2] = 0.61 M, [CO2] = 1.6 M, [H2O] = 1.1 M, [CO] = 1.4 M

c) [HCl] = 1.2 x 10-3 M, [O2] = 3.8 x 10-4 M, [H2O] = 5.8 x 10-2 M, [Cl2] = 5.8 x 10-2 M

d) [NH3] = 0.62 M, [H2] = 0.14 M, [N2] = 0.45 M

e) [H2] = 0.0045 M, [Cl2] = 0.0045 M, [HCl] = 0.0625 M

f) [SO2] = 2.00 M, [O2] = 1.50 M, [SO3] = 3.00 M

回答 (1)

戇戇居士

2016-08-05 7:36 am

1.
a) Kc = [NO]⁴ / ([N₂O]² [O₂])

b) Kc = [H₂O] [CO] / ([H₂] [CO₂])

c) Kc = [Cl₂]² [H₂O]² / ([HCl]⁴ [O₂])

d) Kc = [NH₃]² / ([H₂]³ [N₂])

e) Kc = [HCl]² / ([H₂] [Cl₂])

f) Kc = [SO₃]² / ([SO₂]² [O₂])

2.
a) Kc = (5.6 × 10⁻⁹)⁴ / (0.0035² × 0.0027) = 2.97 × 10⁻²⁶

b) Kc = 1.1 × 1.4 / (0.61 × 1.6) = 1.6

c) Kc = (5.8 × 10⁻²)² (5.8 × 10⁻²)² / {(1.2 × 10⁻³)⁴ × (3.8 × 10⁻⁴)} = 1.4 × 10¹⁰

d) Kc = 0.62² / (0.14³ × 0.45) = 310

e) Kc = 0.0625² / (0.0045 × 0.0045) = 190

f) Kc =3.00² / (2.00² × 1.50) = 1.50

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