Easy algebra 1 word problem that I don't get please help?
2016-08-03 6:45 am
Find 3 consecutive odd integers such that the sum of 7 times the smallest and twice the largest is -91
回答 (4)
2016-08-03 6:49 am
✔ 最佳答案
Let n, (n + 2) and (n + 4) be the three consecutive odd integers.7n + 2(n + 4) = -91
7n + 2n + 8 = -91
9n = -99
n = -11
n + 2 = -9
n + 4 = -7
The three consecutive odd integers are -11, -9 and -7.
2016-08-03 6:52 am
Almost the same problem as 4 minutes ago!
2016-08-03 9:42 am
3 consecutive odd integers such that
the sum of 7 times the smallest and twice the largest is -91:
7(x - 2) + 2(x + 2) = -91
9x = -81
x = -9
The three consecutive odd integers are -11, -9 and -7.
the sum of 7 times the smallest and twice the largest is -91:
7(x - 2) + 2(x + 2) = -91
9x = -81
x = -9
The three consecutive odd integers are -11, -9 and -7.
2016-08-03 7:27 am
Let these 3 be
2k+1, 2k+3, 2k+5
7(2k+1) + 2(2k+5) = -91
14k+7+4k+10 = -91
18k + 17 = -91
18k = -108
k = -108/18 = -6
2k+1 = -11
2k+3 = -9
2k+5 = -7
-11,-9,-7
2k+1, 2k+3, 2k+5
7(2k+1) + 2(2k+5) = -91
14k+7+4k+10 = -91
18k + 17 = -91
18k = -108
k = -108/18 = -6
2k+1 = -11
2k+3 = -9
2k+5 = -7
-11,-9,-7
收錄日期: 2021-05-01 14:16:04
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