When sodium compounds are heated in a bunsen burner flame they emit light at a wavelength of 5890 Å.?
2016-08-03 3:59 am
If 1.0 × 10-4 mole of sodium atoms each emit a photf on of this wavelength how many kJ of energy are emitted
回答 (2)
2016-08-03 4:15 am
Use eq: E= hv=nhc/wavelength
E=( 10^-4)x 6.022 x 10^ 22*(6.626 x 10^ -34)*3 x 10^8/(5890 x 10^-10)
= Solve it and divide by 1000 to get answer in kilojoule.
If u have any more doubt ask in comment box.
Goof bless u.
E=( 10^-4)x 6.022 x 10^ 22*(6.626 x 10^ -34)*3 x 10^8/(5890 x 10^-10)
= Solve it and divide by 1000 to get answer in kilojoule.
If u have any more doubt ask in comment box.
Goof bless u.
2016-08-03 4:11 am
5890 Å = 203.1 kJ/mole
(203.1 kJ/mol) x (1.0 x 10^-4 mol) = 0.02031 kJ
(203.1 kJ/mol) x (1.0 x 10^-4 mol) = 0.02031 kJ
收錄日期: 2021-04-21 19:29:54
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