log4 (7-4x)=1 find x?
回答 (6)
2016-07-30 1:07 pm
log₄(7 - 4x) = 1
log₄(7 - 4x) = log₄(4)
7 - 4x = 4
4x = 3
x = 3/4
log₄(7 - 4x) = log₄(4)
7 - 4x = 4
4x = 3
x = 3/4
2016-07-30 10:15 pm
7 - 4x = 4
3 = 4x
x = 3 / 4
3 = 4x
x = 3 / 4
2016-07-30 4:56 pm
4^1 = 7-4x
4 = 7-4x
-3 = -4x
X = 3/4
Log 4 (7-4(3/4)) = 1
Log 4 (7-3) = 1
Log 4 (4) = 1
4^1 = 4
4 = 4
4 = 7-4x
-3 = -4x
X = 3/4
Log 4 (7-4(3/4)) = 1
Log 4 (7-3) = 1
Log 4 (4) = 1
4^1 = 4
4 = 4
2016-07-30 1:33 pm
log(base 4)(7 - 4x) = 1
4^1 = 7 - 4x
4 = 7 - 4x
-3 = -4x
x = 3/4
4^1 = 7 - 4x
4 = 7 - 4x
-3 = -4x
x = 3/4
2016-07-30 1:24 pm
log(base 4)[7-4x] = 1, ie., 4^1 = 7-4x, ie., 4x = 7-4 = 3, ie., x = (3/4).
2016-07-30 1:06 pm
7-4x=4
-4x= -3
x=3/4
-4x= -3
x=3/4
收錄日期: 2021-04-18 15:22:37
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20160730050251AAuW1in