log4 (7-4x)=1 find x?

2016-07-30 1:02 pm

回答 (6)

2016-07-30 1:07 pm

log₄(7 - 4x) = 1
log₄(7 - 4x) = log₄(4)
7 - 4x = 4
4x = 3
x = 3/4

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2016-07-30 10:15 pm

7 - 4x = 4
3 = 4x
x = 3 / 4

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2016-07-30 4:56 pm

4^1 = 7-4x
4 = 7-4x
-3 = -4x
X = 3/4
Log 4 (7-4(3/4)) = 1
Log 4 (7-3) = 1
Log 4 (4) = 1
4^1 = 4
4 = 4

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2016-07-30 1:33 pm

log(base 4)(7 - 4x) = 1
4^1 = 7 - 4x
4 = 7 - 4x
-3 = -4x
x = 3/4

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2016-07-30 1:24 pm

log(base 4)[7-4x] = 1, ie., 4^1 = 7-4x, ie., 4x = 7-4 = 3, ie., x = (3/4).

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2016-07-30 1:06 pm

7-4x=4
-4x= -3
x=3/4

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