How many liters of H2 would be formed at 536 mm Hg and 13 ∘C if 22.5 g of zinc was allowed to react?
回答 (1)
2016-07-29 5:40 pm
P = 536 mmHg
V = ? L
n = 22.5/65.38 mol
R = 62.36 mmHg L / (mol K)
T = (273 + 13) K = 286 K
PV = nRT
V = nRT/P
Volume, V = (22.5/65.38) × 62.36 × 286 / 536 = 11.5 L
V = ? L
n = 22.5/65.38 mol
R = 62.36 mmHg L / (mol K)
T = (273 + 13) K = 286 K
PV = nRT
V = nRT/P
Volume, V = (22.5/65.38) × 62.36 × 286 / 536 = 11.5 L
收錄日期: 2021-05-01 13:46:16
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20160729090654AA12Zuc