Simplify 1+cot^2x / secx.
PLEASE HELP. Please show work.
Simplifying Trig Expressions?
2016-07-29 7:42 am
回答 (1)
2016-07-29 7:50 am
(1 + cot²x) / secx
= [1 + (cos²x / sin²x)] / (1 / cosx)
= [(sin²x + cos²x) / sin²x] / (1 / cosx)
= (1 / sin²x) / (1 / cosx)
= cosx / sin²x
(The answer can be rewritten as secx cotx.)
= [1 + (cos²x / sin²x)] / (1 / cosx)
= [(sin²x + cos²x) / sin²x] / (1 / cosx)
= (1 / sin²x) / (1 / cosx)
= cosx / sin²x
(The answer can be rewritten as secx cotx.)
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