2.Hydrogen and oxygen react to produce water, according to the reaction 2H2 (g) + O2 (g) --> 2H2O (l). If 3 moles of hydrogen react with 2 moles of oxygen and the yield in the reaction is 80 percent, how many moles of water are obtained?
a. 2 moles
b. 2.4 moles
c. 2.7 moles
d. 3 moles
how many moles of water are obtained?
2016-07-25 5:22 pm
回答 (1)
2016-07-25 5:36 pm
2.
2H₂(g) + O₂(g) → 2H₂O(l)
OR: Mole ratio H₂ : O₂ : H₂O = 2 : 1 : 2
If 3 moles of H₂ completely reacts :
Actual o. of moles of H₂O obtained = (3 mol) × (2/2) × 80% = 2.4 mol
If 2 moles of O₂ completely reacts :
Actual no. of moles of H₂O obtained = (2 mol) × 2 × 80% = 3.2 mol
The limiting reactant (limiting reagent) gives the smaller yield.
Hence, H₂ is the limiting reactant.
Actual o. of moles of H₂O obtained = 2.4 mol
...... Answer : b. 2.4 mol
2H₂(g) + O₂(g) → 2H₂O(l)
OR: Mole ratio H₂ : O₂ : H₂O = 2 : 1 : 2
If 3 moles of H₂ completely reacts :
Actual o. of moles of H₂O obtained = (3 mol) × (2/2) × 80% = 2.4 mol
If 2 moles of O₂ completely reacts :
Actual no. of moles of H₂O obtained = (2 mol) × 2 × 80% = 3.2 mol
The limiting reactant (limiting reagent) gives the smaller yield.
Hence, H₂ is the limiting reactant.
Actual o. of moles of H₂O obtained = 2.4 mol
...... Answer : b. 2.4 mol
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