﹝x+1﹞²﹝x-1﹞²﹝x²+1﹞² 乘法公式展開?
回答 (1)
2016-07-25 6:22 am
(x+1)^2 (x-1)^2 (x^2 +1)^2
=[(x^2 -1)(x^2+1)]^2
=(x^4-1)^2
=x^8-2x^4+1
=[(x^2 -1)(x^2+1)]^2
=(x^4-1)^2
=x^8-2x^4+1
收錄日期: 2021-04-18 15:20:19
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20160724202130AAVv7Ix