Find the distance between point G(5,3) and H(-6,4)., 10 points awarded for time thank you!?
回答 (4)
2016-07-20 7:54 pm
✔ 最佳答案
d² = [ - 6 - 5]² + [4 - 3]²d² = 121 + 1
d² = 122
d = 11.05
2016-07-20 6:21 pm
Distance between G and H
= √{[5 - (-6)]² + (3 - 4)²}
= √[11² + (-1)²]
= √(121 + 1)
= √122 (units)
= √{[5 - (-6)]² + (3 - 4)²}
= √[11² + (-1)²]
= √(121 + 1)
= √122 (units)
2016-07-20 7:12 pm
Pythagoras
r^2 = 121+1 = 122
r = sqrt(122)
r^2 = 121+1 = 122
r = sqrt(122)
2016-07-20 6:30 pm
(5,3) & (-6,4)
d² = (5--6)² + (3-4)² = 11² + 1 = 122
d = √122
d² = (5--6)² + (3-4)² = 11² + 1 = 122
d = √122
收錄日期: 2021-05-01 14:15:05
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