And .0116 M NH3 at equilibrium? The overall Kf for Zn(NH3)4^2+ is 3.8 X 10^9.
How do I do this problem?
A) 2.9 X 10^-3
B) 8.8 X 10^-3
C) 6.7 X 10^-4
D) 2.0 X 10^-13
收錄日期: 2021-04-20 16:27:53
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20160720082815AAh4NQl