Solve the inequality. Write the solution set in interval notation. 9x + 7 ≥ 5x + 3x?
回答 (14)
2016-07-20 8:51 am
9x + 7 ≥ 5x + 3x
9x + 7 ≥ 8x
9x + 7 - 8x - 7 ≥ 8x - 8x - 7
x ≥ -7
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If the inequality is 9x + 7 ≥ 5x + 3 instead, then :
9x + 7 ≥ 5x + 3
9x + 7 - 5x - 7 ≥ 5x + 3 - 5x - 7
4x ≥ -4
x ≥ -1
9x + 7 ≥ 8x
9x + 7 - 8x - 7 ≥ 8x - 8x - 7
x ≥ -7
====
If the inequality is 9x + 7 ≥ 5x + 3 instead, then :
9x + 7 ≥ 5x + 3
9x + 7 - 5x - 7 ≥ 5x + 3 - 5x - 7
4x ≥ -4
x ≥ -1
2016-07-20 8:49 am
OK, here we go :)
9x + 7 ≥ 5x + 3x
9x + 7 ≥ 8x
9x - 8x + 7 ≥ 8x - 8x
x + 7 ≥ 0
x + 7 - 7 ≥ 0 - 7
x ≥ - 7
In interval notation, this an be expressed as: [- 7, ∞ ).
Keep in mind that a square bracket [ ] includes an endpoint and a ( ) bracket excludes an endpoint.
Here, - 7 is included, but ∞ is excluded since it is not a defined number.
Hope this helps !!!!!!!!!!!!!!!!!!!!!
9x + 7 ≥ 5x + 3x
9x + 7 ≥ 8x
9x - 8x + 7 ≥ 8x - 8x
x + 7 ≥ 0
x + 7 - 7 ≥ 0 - 7
x ≥ - 7
In interval notation, this an be expressed as: [- 7, ∞ ).
Keep in mind that a square bracket [ ] includes an endpoint and a ( ) bracket excludes an endpoint.
Here, - 7 is included, but ∞ is excluded since it is not a defined number.
Hope this helps !!!!!!!!!!!!!!!!!!!!!
2016-07-22 7:35 am
Given inequality-
9x+7 ≥ 5x+3x
9x+7 ≥ 8x
9x-8x+7 ≥ 8x-8x
x+7 ≥ 0
x+7-7 ≥ 0-7
x ≥ -7
Solution in interval notation- x belongs to [-7 , ∞)
9x+7 ≥ 5x+3x
9x+7 ≥ 8x
9x-8x+7 ≥ 8x-8x
x+7 ≥ 0
x+7-7 ≥ 0-7
x ≥ -7
Solution in interval notation- x belongs to [-7 , ∞)
2016-07-20 10:30 am
9x + 7 ≥ 5x + 3x
9x + 7 ≥ 8x
9x - 8x + 7 ≥ 8x - 8x
x + 7 ≥ 0
x ≥ - 7
therefore it belongs to [-7,infinity)
9x + 7 ≥ 8x
9x - 8x + 7 ≥ 8x - 8x
x + 7 ≥ 0
x ≥ - 7
therefore it belongs to [-7,infinity)
2016-08-25 6:04 am
x awesomeer than or equal to -7
2016-07-27 6:38 am
4x + 7 ≥ 5x + 3x?
9x + 7 ≥ 5x + 3x
9x – 5x – 3x ≥ - 7
9x – 8x ≥ - 7
x ≥ - 7 → (≥ means exactly – 7 value)
Interval nature x belongs to [- 7, ∞]
(∵ [- Exact value = - 7])
(∴ (- ∞ in between value)
9x + 7 ≥ 5x + 3x
9x – 5x – 3x ≥ - 7
9x – 8x ≥ - 7
x ≥ - 7 → (≥ means exactly – 7 value)
Interval nature x belongs to [- 7, ∞]
(∵ [- Exact value = - 7])
(∴ (- ∞ in between value)
2016-07-24 1:22 am
x≥-7
2016-07-23 11:47 am
9x - 8x ≥ -7
x ≥ -7
x ≥ -7
2016-07-22 2:02 pm
x greater than or equal to -7
2016-07-22 1:02 pm
9x + 7 ≥ 5x + 3x
x ≥ -7
x ≥ -7
2016-07-21 5:42 pm
9x + 7 ≥ 5x + 3x
or 9x - 5x - 3x ≥ -7
or x ≥ - 7
or 9x - 5x - 3x ≥ -7
or x ≥ - 7
2016-07-21 6:11 am
9x + 7 ≥ 5x + 3x
Or,
9x + 7 ≥ 8x, ==> x + 7 - 8x ≥ 8x - 8x,
Or,
x ≥ -7
Or,
9x + 7 ≥ 8x, ==> x + 7 - 8x ≥ 8x - 8x,
Or,
x ≥ -7
2016-07-20 5:25 pm
9x+7 >= 8x
subtract 8x from both sides
x + 7 >= 0
subtract 7 from both sides
x >= -7
[-7, infinity)
subtract 8x from both sides
x + 7 >= 0
subtract 7 from both sides
x >= -7
[-7, infinity)
2016-07-20 10:07 am
9x + 7 ≥ 5x + 3x
9x - 5x - 3x ≥ -7
x ≥ - 7
___________-7_/_/_/_/_/_/_/_/_/_ including point -7
Answer: [- 7, ∞ )
9x - 5x - 3x ≥ -7
x ≥ - 7
___________-7_/_/_/_/_/_/_/_/_/_ including point -7
Answer: [- 7, ∞ )
2016-07-20 8:59 am
x ≥ - 7
2016-07-20 11:06 am
9x+7≥5x+3
9x-5x≥3-7
4x≥-4
x≥-1 final answer
9x-5x≥3-7
4x≥-4
x≥-1 final answer
2016-07-20 8:47 am
x belong to (-7,∞)
收錄日期: 2021-04-18 15:20:09
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