Solve the inequality. Write the solution set in interval notation. 9x + 7 ≥ 5x + 3x?

9x + 7 ≥ 5x + 3x
9x + 7 ≥ 8x
9x + 7 - 8x - 7 ≥ 8x - 8x - 7
x ≥ -7


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If the inequality is 9x + 7 ≥ 5x + 3 instead, then :
9x + 7 ≥ 5x + 3
9x + 7 - 5x - 7 ≥ 5x + 3 - 5x - 7
4x ≥ -4
x ≥ -1

OK, here we go :)

9x + 7 ≥ 5x + 3x
9x + 7 ≥ 8x
9x - 8x + 7 ≥ 8x - 8x
x + 7 ≥ 0
x + 7 - 7 ≥ 0 - 7
x ≥ - 7

In interval notation, this an be expressed as: [- 7, ∞ ).

Keep in mind that a square bracket [ ] includes an endpoint and a ( ) bracket excludes an endpoint.
Here, - 7 is included, but ∞ is excluded since it is not a defined number.

Hope this helps !!!!!!!!!!!!!!!!!!!!!

Given inequality-
9x+7 ≥ 5x+3x
9x+7 ≥ 8x
9x-8x+7 ≥ 8x-8x
x+7 ≥ 0
x+7-7 ≥ 0-7
x ≥ -7

Solution in interval notation- x belongs to [-7 , ∞)

9x + 7 ≥ 5x + 3x
9x + 7 ≥ 8x
9x - 8x + 7 ≥ 8x - 8x
x + 7 ≥ 0
x ≥ - 7

therefore it belongs to [-7,infinity)

x awesomeer than or equal to -7

4x + 7 ≥ 5x + 3x?
9x + 7 ≥ 5x + 3x
9x – 5x – 3x ≥ - 7
9x – 8x ≥ - 7
x ≥ - 7 → (≥ means exactly – 7 value)
Interval nature x belongs to [- 7, ∞]
(∵ [- Exact value = - 7])
(∴ (- ∞ in between value)

x≥-7

9x - 8x ≥ -7

x ≥ -7

x greater than or equal to -7

9x + 7 ≥ 5x + 3x
x ≥ -7

9x + 7 ≥ 5x + 3x
or 9x - 5x - 3x ≥ -7

or x ≥ - 7

9x + 7 ≥ 5x + 3x
Or,
9x + 7 ≥ 8x, ==> x + 7 - 8x ≥ 8x - 8x,






Or,

x ≥ -7

9x+7 >= 8x
subtract 8x from both sides
x + 7 >= 0
subtract 7 from both sides
x >= -7

[-7, infinity)

9x + 7 ≥ 5x + 3x
9x - 5x - 3x ≥ -7
x ≥ - 7
___________-7_/_/_/_/_/_/_/_/_/_ including point -7
Answer: [- 7, ∞ )

x ≥ - 7

9x+7≥5x+3
9x-5x≥3-7
4x≥-4
x≥-1 final answer

x belong to (-7,∞)