Factorise 3+2x-x^2 please!?
回答 (7)
2016-07-19 5:20 pm
3 + 2x - x²
= (3 - x) + x + 2x - x²
= (3 - x) + 3x - x²
= (3 - x) + (3x - x²)
= (3 - x) + x(3 - x)
= (1 - x)(3 - x)
= (3 - x) + x + 2x - x²
= (3 - x) + 3x - x²
= (3 - x) + (3x - x²)
= (3 - x) + x(3 - x)
= (1 - x)(3 - x)
2016-07-19 5:20 pm
-(x^2 - 2*x - 3)
-(x + 1)*(x - 3)
(x + 1)*(3 - x) <<<
-(x + 1)*(x - 3)
(x + 1)*(3 - x) <<<
2016-07-20 6:30 am
-(x-3)(x+1)
2016-07-19 10:43 pm
(-x +1) (x+1)
2016-07-19 5:42 pm
3 + 2x - x^2
= (3 - x)(x + 1)
= (3 - x)(x + 1)
2016-07-19 5:24 pm
3 + 2x − x²
= −(x² − 2x − 3)
= −(x − 3) (x + 1)
2016-07-19 5:23 pm
-1(x² - 2x - 3) = -1(x - 3)(x + 1) or (3 - x)(1 + x)
收錄日期: 2021-04-20 16:31:20
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