MATH HELP ASAP?
2016-07-15 5:25 pm
if ø is between 0 degrees and 90 degress, and sinø=3/5, what is the value of cotø
回答 (6)
2016-07-15 5:39 pm
When 0 ≤ ø ≤ 90°, all trigonometric functions are positive.
sin²ø + cos²ø = 1
(3/5)² + cos²ø = 1
(9/25) + cos²ø = 1
cos²ø = 1 - (9/25)
cos²ø = 16/25
cosø = 4/5 for cosø > 0
cotø = cosø / sinø
cotø = (4/5) / (3/5)
cotø = (4/5) × (5/3)
cotø = 4/3
sin²ø + cos²ø = 1
(3/5)² + cos²ø = 1
(9/25) + cos²ø = 1
cos²ø = 1 - (9/25)
cos²ø = 16/25
cosø = 4/5 for cosø > 0
cotø = cosø / sinø
cotø = (4/5) / (3/5)
cotø = (4/5) × (5/3)
cotø = 4/3
2016-07-15 6:58 pm
The easy way is to sketch a 3-4-5 triangle. Mark ø (formed by the 4 and 5 sides) and you see this makes sinø=3/5.
cotø = 1/tanø = 1/(3/4) = 4/3
cotø = 1/tanø = 1/(3/4) = 4/3
2016-07-15 5:32 pm
As ø is in quadrant 1, all ratios are positive.
So, if sinø = 3/5 then cosø = 4/5 and tanø = 3/4
Now, cotø => 1/tanø = 1/(3/4)....i.e. 4/3
:)>
So, if sinø = 3/5 then cosø = 4/5 and tanø = 3/4
Now, cotø => 1/tanø = 1/(3/4)....i.e. 4/3
:)>
2016-07-15 11:02 pm
sin ø = 3/5
cos ø = 4/5
tan ø = 3/4
cot ø = 4/3
cos ø = 4/5
tan ø = 3/4
cot ø = 4/3
2016-07-15 6:29 pm
sinθ = 3/5
cosθ = 4/5
cotθ = cosθ/sinθ = 4/3
cosθ = 4/5
cotθ = cosθ/sinθ = 4/3
2016-07-15 6:00 pm
If ø is between 0 degrees and 90 degress, and sin ø = 3/5,
the value of cot ø is 4/3.
the value of cot ø is 4/3.
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