MATH HELP ASAP?

When 0 ≤ ø ≤ 90°, all trigonometric functions are positive.

sin²ø + cos²ø = 1
(3/5)² + cos²ø = 1
(9/25) + cos²ø = 1
cos²ø = 1 - (9/25)
cos²ø = 16/25
cosø = 4/5 for cosø > 0

cotø = cosø / sinø
cotø = (4/5) / (3/5)
cotø = (4/5) × (5/3)
cotø = 4/3

The easy way is to sketch a 3-4-5 triangle. Mark ø (formed by the 4 and 5 sides) and you see this makes sinø=3/5.

cotø = 1/tanø = 1/(3/4) = 4/3

As ø is in quadrant 1, all ratios are positive.

So, if sinø = 3/5 then cosø = 4/5 and tanø = 3/4

Now, cotø => 1/tanø = 1/(3/4)....i.e. 4/3

:)>

sin ø = 3/5
cos ø = 4/5
tan ø = 3/4
cot ø = 4/3

sinθ = 3/5
cosθ = 4/5
cotθ = cosθ/sinθ = 4/3

If ø is between 0 degrees and 90 degress, and sin ø = 3/5,
the value of cot ø is 4/3.