What is the slope of y=311.111x+1533.333? It is the equation of a scatterplot?

The slope of the equation (y = mx + c) = m

Hence, the slope of the equation (y = 311.111x + 1533.333) = 311.111

The equation is in the format y=mx+b. m is the slope. Therefore the slope is 311.111. No, it is not the equation of a scatter plot. It's a line. Scatter plots don't have equations. You can make an equation for the line that fits a particular scatter plot the best, but you won't be learning about that until Algebra II.

This is a very simple question if you know the slope intercept form and the parts of it y=mx+b
Mx- the slope b-the y intercept
In your equation mx-311.111x therefore the slope is 311.111

The slope of anything in the format y = mx +c is m.

So the slope of your equation is 311.111

Eqn is in slope y-intercept form y = mx + b, where m is the slope and b is the y-intercept. Then m = 311.111 = tan(89.81583556 deg.)

Presuming those are not terminating decimals and that they do go on forever, it would be more accurate to represent them as fractions.

y = (2800/9)x + (4600/3)

So your slope is (2800/9).

The slope is the coefficient of x.
311.111

It is the equation of a line that approximates the unknown equation for the data shown in the scatter plot.

311.111 ~ 2.8e3/9
1533.333 ~ 4.6e3/3

These nice round figures do not happen in nature. So they are a numerical approximation to data.

311.111