What is the slope of y=311.111x+1533.333? It is the equation of a scatterplot?
回答 (8)
The slope of the equation (y = mx + c) = m
Hence, the slope of the equation (y = 311.111x + 1533.333) = 311.111
The equation is in the format y=mx+b. m is the slope. Therefore the slope is 311.111. No, it is not the equation of a scatter plot. It's a line. Scatter plots don't have equations. You can make an equation for the line that fits a particular scatter plot the best, but you won't be learning about that until Algebra II.
This is a very simple question if you know the slope intercept form and the parts of it y=mx+b
Mx- the slope b-the y intercept
In your equation mx-311.111x therefore the slope is 311.111
The slope of anything in the format y = mx +c is m.
So the slope of your equation is 311.111
Eqn is in slope y-intercept form y = mx + b, where m is the slope and b is the y-intercept. Then m = 311.111 = tan(89.81583556 deg.)
Presuming those are not terminating decimals and that they do go on forever, it would be more accurate to represent them as fractions.
y = (2800/9)x + (4600/3)
So your slope is (2800/9).
The slope is the coefficient of x.
311.111
It is the equation of a line that approximates the unknown equation for the data shown in the scatter plot.
311.111 ~ 2.8e3/9
1533.333 ~ 4.6e3/3
These nice round figures do not happen in nature. So they are a numerical approximation to data.
收錄日期: 2021-05-01 13:09:46
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20160713113203AAIQd1V
檢視 Wayback Machine 備份