How would I solve this basic algebra equation?
I have never been taught algebra and would like to know how I would solve this algorithm.
x - 4 - [(1/6 + 1/12 + 1/7) x + 5] = ?
回答 (5)
x - 4 - [(1/6 + 1/12 + 1/7) x + 5]
= x - 4 - [(14/84 + 7/84 + 12/84) x + 5]
= x - 4 - [(33/84) x + 5]
= x - 4 - [(11/28) x + 5]
= x - 4 - (11/28) x - 5
= x - (11/28) x - 4 - 5
= (28/28) x - (11/28) x - 9
= (17/28) x - 9
1/6 + 1/12 + 1/7= 1/4+1/7= 11/28
x -4 -(11x/28 +5)
=x -4 -11x/28 -5
=17x/28 -9
x - 4 - [(1/6 + 1/12 + 1/7) x + 5] = ?
This is not an equation ... and not an algorithm. It cannot be solved.
This is an algebraic expression ... it can be simplified by combining like terms.
x - 4 - [(1/6 + 1/12 + 1/7) x + 5] <<< start inner most .. adding fractions
= x - 4 - [(14/84 + 7/84 + 12/84)x + 5]
= x - 4 - [(33/84)x + 5]
= x - 4 - [(11/28)x + 5] <<< distribute the neg.
= x - 4 - (11/28)x - 5 <<< commutative prop. ... rearrange
= 1x - (11/28)x - 4 - 5 <<< combine like terms
= (17/28)x - 9 <<< answer ... nothing more can be done.
x - 4 - [ 14/84 + 7/84 + 12/84 ] x + 5
x - 4 - [ 33/84 ] x + 5
[51/84 ] x + 1
Pftt stupid white morons. I would hardly consider this "algebra" or "algorithm"; this is just simple rudimentary arithmetic. And like I'm gonna solve anything for a ******* stupid white boy.
收錄日期: 2021-04-20 16:26:07
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