更新1:
...CONTINUED: what is the concentration of OH- in solution?
For the reaction KOH(aq) --> K+(aq) + OH-(aq) , K = .316. If the concentration of KOH is 4.75M at equilibrium, what is the concentration...?
回答 (1)
2016-07-12 7:09 am
✔ 最佳答案
KOH(aq) ⇌ K⁺(aq) + OH⁻(aq) ...... K = 0.316At equilibrium :
[KOH] = 4.75 M
[K⁺] = [OH⁻] = y M
K = [K⁺][OH⁻] / [KOH]
0.316 = y² / 4.75
y² = 0.316 × 4.75
y = 1.23 M
[OH⁻] at equilibrium = 1.23 M
收錄日期: 2021-04-18 15:25:02
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20160711230334AApZGSa