SO3 (1.27×10-2 M), SO2 (4.11×10-2 M), and O2 (2.68×10-2 M). What is the value of the equilibrium constant for this reaction at 1300 K?
回答 (1)
2016-07-12 11:02 am
For the reaction : 2SO₃(g) ⇌ 2SO₂(g) + O₂(g)
Equilibrium constant, Kc
= [SO₂]² [O₂] / [SO₃]²
= (4.11 × 10⁻²)² × (2.68 × 10⁻²) / (1.27 × 10⁻²)²
= 0.281 (mol/L)
For the reaction : 2SO₂(g) + O₂(g) ⇌ 2SO₃(g)
Equilibrium constant, Kc
= [SO₃]² / ([SO₂]² [O₂])
= (1.27 × 10⁻²)² / {(4.11 × 10⁻²)² × (2.68 × 10⁻²)}
= 3.56 (L/mol)
Equilibrium constant, Kc
= [SO₂]² [O₂] / [SO₃]²
= (4.11 × 10⁻²)² × (2.68 × 10⁻²) / (1.27 × 10⁻²)²
= 0.281 (mol/L)
For the reaction : 2SO₂(g) + O₂(g) ⇌ 2SO₃(g)
Equilibrium constant, Kc
= [SO₃]² / ([SO₂]² [O₂])
= (1.27 × 10⁻²)² / {(4.11 × 10⁻²)² × (2.68 × 10⁻²)}
= 3.56 (L/mol)
收錄日期: 2021-04-18 15:14:14
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