Which shows the equation below written in the form ax2 + bx + c = 0?
2x2 - 3 = -6x - 2
A. 2x2 + 6x - 5 = 0
B. 2x2 - 6x - 1 = 0
C. 2x2 + 6x - 1 = 0
D. 2x2 - 6x - 5 = 0
Help me please!?
2016-07-11 4:49 pm
回答 (4)
2016-07-11 4:53 pm
✔ 最佳答案
2x² - 3 = -6x - 2Adding 6x to both sides gives:
2x² + 6x - 3 = -2
Adding 2 to both sides gives:
2x² + 6x - 3 + 2 = 0
i.e. 2x² + 6x - 1 = 0...option C
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2016-07-12 4:30 pm
Which shows the equation below
written in the form ax^2 + bx + c = 0?
2x^2 - 3 = -6x - 2
Answer choice:
C. 2x^2 + 6x - 1 = 0
written in the form ax^2 + bx + c = 0?
2x^2 - 3 = -6x - 2
Answer choice:
C. 2x^2 + 6x - 1 = 0
2016-07-11 5:02 pm
If you can see that 2 - 3 = -1 it tells you it was c)
2016-07-11 4:52 pm
NOTE: We use the ^ symbol to denote exponents.
2x^2 − 3 = −6x − 2
2x^2 − 3 + 6x + 2 = 0
2x^2 + 6x − 1 = 0
收錄日期: 2021-05-01 21:05:15
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