11 - 4x = (3x - 2)2 + 1
A. 9x2 - 16x + 16 = 0
B. 9x2 - 16x - 6 = 0
C. 9x2 - 8x - 6 = 0
D. 9x2 - 8x + 16 = 0
Which shows the equation below written in standard form?
2016-07-11 3:38 pm
回答 (4)
2016-07-11 3:42 pm
✔ 最佳答案
You MUST use the caret ^ (above the 6) to denote an exponent !!11 - 4x = (3x - 2)^2 + 1
11 - 4x = 9x^2 - 12x + 4 + 1
9x^2 - 8x - 6 = 0
2016-07-11 3:47 pm
I assume you mean 11 - 4x = (3x - 2)² + 1
so, 11 - 4x = 9x² - 12x + 4 + 1
i.e. 11 - 4x = 9x² - 12x + 5
=> 9x² - 12x + 4x + 5 - 11 = 0
Hence, 9x² - 8x - 6 = 0
:)>
so, 11 - 4x = 9x² - 12x + 4 + 1
i.e. 11 - 4x = 9x² - 12x + 5
=> 9x² - 12x + 4x + 5 - 11 = 0
Hence, 9x² - 8x - 6 = 0
:)>
2016-07-11 3:44 pm
Drop the course. It is too hard for you.
2016-07-11 6:30 pm
11 - 4x = (3x - 2)^2 + 1
9x^2 - 8x - 6 = 0
Answer choice:
C. 9x^2 - 8x - 6 = 0
9x^2 - 8x - 6 = 0
Answer choice:
C. 9x^2 - 8x - 6 = 0
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