(a^m- a^n)(b^m+b^n)?
回答 (2)
-a^n * b^n -a^n * b^m + a^m * b^n + a^m b^m
(a^m- a^n)(b^m+b^n)
=(ab)^m +(a^m)(b^n)-(a^n)(b^m)-(ab)^n
收錄日期: 2021-04-18 15:13:32
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