(2^5) × (2^7) × (4^(-3)) × (8^3) =2的幾次方 請詳答!?

Sol
(2^5)*(2^7)*[4^(－3)]*(8^3)
=(2^5)*(2^7)*[(2^2)^(－3)]*[(2^3)^3]
=(2^5)*(2^7)*[2^(－6)]^(2^9)
=2^(5+7－6+9)
=2^15

(2^5)(2^7)[4^(-3)](8^3)
=[2^(5+7)](2^9)/(2^6)
=2^(5+7+9-6)
=2^15