what is the specific gravity of the new solution?

Method 1 :

Density of antifreeze = 0.8 kg/L
Density of water = 1 kg/L
Volume of antifreeze = 3.8 L
Volume of water = 5.6 L

Total mass of the new solution
= (0.8 × 3.8 + 1 × 5.6) kg
= 8.64 kg

Total volume of the new solution
= (3.8 + 5.6) L
= 9.4 L

Density of the new solution
= Mass / Volume
= 8.64/9.4 kg/L
= 0.92 kg/L

Specific gravity of the new solution
= 0.92

...... The answer is : 0.92


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Method 2 :

Specific gravity of the new solution
= (0.8 × 3.8 + 1 × 5.6) / (3.8 + 5.6)
= 0.92

...... The answer is : 0.92

Specific gravity = Density of a solution ÷ Density of water
0.8 = D ÷ 9.8
D = 7.84 g/L

Density = Mass ÷ Volume
The first step is to determine the mass of antifreeze and water. To do this, multiply the volume by the density.

M1 = 3.8 * 7.84 = 29.792 g
M2 = 5.6 * 9.8 = 54.88 g
Total mass = 84.672 g
Total volume = 3.8 + 5.6 = 9.4 L

D = 84.672 ÷ 9.4
The density of the solution is 9 g/L.

Specific gravity = 9 ÷ 9.8
This is approximately 0.92

0.92