could someone help me prove this trig identity sin(pi/2 +x) = cos(x)?

Trigonometric identity : sin(A - B) = sin(A) cos(B) - cos(A) sin(B)

Sin[(π/2) - x]
= sin(π/2) cos(x) - cos(π/2) sin(x)
= 1 × cos(x) - 0 × sin(x)
= cos(x)

sin(π/2 + x) = sin(π/2)cos(x) + cos(π/2)sin(x)
= 1·cos(x) + 0·sin(x)
= cos(x)

Hint: sin(A + B) = sinA cosB + cosA sinB

bonjour