Find f '(a). f(t) = 2t + 2/(t + 3)?
回答 (1)
2016-07-03 4:49 pm
f(t) = 2t + [2/(t + 3)]
f'(t) = (d/dt){2t + [2/(t + 3)]}
= (d/dt)(2t) + (d/dt)[2/(t + 3)
= 2 + [-2/(t + 3)²]
= 2 - [2/(t + 3)²]
f'(a) = 2 - [2/(a + 3)²]
f'(t) = (d/dt){2t + [2/(t + 3)]}
= (d/dt)(2t) + (d/dt)[2/(t + 3)
= 2 + [-2/(t + 3)²]
= 2 - [2/(t + 3)²]
f'(a) = 2 - [2/(a + 3)²]
收錄日期: 2021-05-01 13:10:28
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20160703084355AA8op94