Use the Law of Cosines to solve the triangle. Round your answers to two decimal places.?

2016-06-30 7:50 pm
C = 100°, a = 3/8, b = 3/4

c=
A=
B=

回答 (1)

2016-06-30 8:21 pm
c² = a² + b² - 2 a b cosC (cosine law)
c² = (3/8)² + (3/4)² - 2 × (3/8) × (3/4) × cos100°
c = √[(3/8)² + (3/4)² - 2 × (3/8) × (3/4) × cos100°]
c = 0.8949
c = 0.89 (to 2 decimal places)

cosA = (b² + c² - a²) / (2 b c) (cosine law)
cosA = [(3/4)² + (0.8949)² - (3/8)²] / [2 × (3/4) × 0.8949]
A = cos⁻¹{[(3/4)² + (0.8949)² - (3/8)²] / [2 × (3/4) × 0.8949]}
A = 24.37°

B = 180° - 100° - 24.37°
B = 55.63°


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