the sum of four consecutive integers is 2016. what are the integers?
回答 (5)
2016-06-26 10:00 pm
Let n, (n + 1), (n + 2) and (n + 3) be the four consecutive integers.
n + (n + 1) + (n + 2) + (n + 3) = 2016
4n + 6 = 2016
4n = 2010
n = 502.5
n ≠ integer
Hence, there is no solution.
n + (n + 1) + (n + 2) + (n + 3) = 2016
4n + 6 = 2016
4n = 2010
n = 502.5
n ≠ integer
Hence, there is no solution.
2016-06-26 9:59 pm
x + (x + 1) + (x + 2) + (x + 3) = 2016
4x + 6 = 2016
4x = 2010
x = 2010/4 = 502.5
not an integer!
double check your question
4x + 6 = 2016
4x = 2010
x = 2010/4 = 502.5
not an integer!
double check your question
2016-06-26 9:59 pm
x + (x + 1) + (x + 2) + (x + 3) = 2016
4x + 6 = 2016
4x = 2010
x = 502.5
As Sqdancefan was saying, there are no "integers" that solve this problem.
4x + 6 = 2016
4x = 2010
x = 502.5
As Sqdancefan was saying, there are no "integers" that solve this problem.
2016-06-26 9:57 pm
The sum of four consecutive integers cannot be 2016. Four consecutive integers will have a sum that gives 2 as a remainder when divided by 4.
2016-06-26 9:55 pm
idk
收錄日期: 2021-04-18 15:11:49
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