Calculus word problem Please Help?

x cm : the length of the side of the square
A cm³ : the area of the square

When A = 16 :
16 = x²
x = 4 or x = -4 (rejected)

A = x²
dA/dt = 2x (dx/dt)

When dx/dt = 2 and x = 4 :
dA/dt = 2 * 4 * 2
dA/dt = 16

The rate of the increase of the area = 16 cm²/s

Let side of the square be denoted as x and area as A.
dx/dt = 2,
A = 16,
A = x^2, x = A^(0.5),
dA/dt = d (x^2)/dt = 2x*dx/dt = 2*[A^(0.5)] *dx/dt = 2 * 4 * 2 = 16cm^2

A = s² --- {When the area of the square is 16 cm², the side length is 4 cm}

dA/dt = 2s • ds/dt

dA/dt = 2(4) • (2)

dA/dt = 16 cm²