If I have a 10,000 gallon pool at 70degrees F and add 350 gallons at 100 degrees F what will the resulting temp be of the 10,350 gallons?
回答 (2)
2016-06-25 5:02 pm
✔ 最佳答案
(10,000 · 70 + 350·100)/10,350 = 71,01 degrees
2016-06-25 5:20 pm
Let T°F be the resulting temperature.
Heat change per gallon per °F = c J
Heat gain of the 10,000 gallons at 70°F = Heat loss of the 350 gallons at 100°F
10,000 × c × (T - 70) = 350 × c × (100 - T)
10,000 × (T - 70) = 350 × (100 - T)
10,000T - 700,000 = 35,000 - 350T
10,350T = 735,000
T = 71
The resulting temperature = 71°F
Heat change per gallon per °F = c J
Heat gain of the 10,000 gallons at 70°F = Heat loss of the 350 gallons at 100°F
10,000 × c × (T - 70) = 350 × c × (100 - T)
10,000 × (T - 70) = 350 × (100 - T)
10,000T - 700,000 = 35,000 - 350T
10,350T = 735,000
T = 71
The resulting temperature = 71°F
收錄日期: 2021-04-18 15:19:19
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