f(x)=ax^5+bx^3+cx-1已知f(-5)=8,則f(5)=?
回答 (1)
2016-06-25 6:24 pm
f(x) = ax⁵ + bx³ + cx - 1
f(-5) = 8
a(-5)⁵ + b(-5)³ + c(-5) - 1 = 8
-125a - 25b - 5c = 9
125a + 25b + 5c = -9
f(5)
= a(5)⁵ + b(5)³ + c(5) - 1
= (125a + 25b + 5c) - 1
= (-9) - 1
= -10
f(-5) = 8
a(-5)⁵ + b(-5)³ + c(-5) - 1 = 8
-125a - 25b - 5c = 9
125a + 25b + 5c = -9
f(5)
= a(5)⁵ + b(5)³ + c(5) - 1
= (125a + 25b + 5c) - 1
= (-9) - 1
= -10
收錄日期: 2021-04-18 15:12:43
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20160625052233AAvKP4z