f(x)=ax^5+bx^3+cx-1已知f(-5)=8,則f(5)=?
回答 (2)
2016-06-26 4:56 am
f(x)=ax^5+bx^3+cx-1
8=-3125a-125b-5c-1
3125a+125b+5c=-9
f(5)=3125a+125b+5c-1
f(5)=-9-1
f(5)=-10
8=-3125a-125b-5c-1
3125a+125b+5c=-9
f(5)=3125a+125b+5c-1
f(5)=-9-1
f(5)=-10
2016-06-26 3:44 am
a(-5)^5+b(-5)^3+c(-5)-1=8
→-3125a-125b-5c=9
→3125a+125b+5c=-9
a(5)^5+b(5)^3+c(5)-1
=(3125a+125b+5c)-1
=-9-1=-10
→-3125a-125b-5c=9
→3125a+125b+5c=-9
a(5)^5+b(5)^3+c(5)-1
=(3125a+125b+5c)-1
=-9-1=-10
收錄日期: 2021-04-18 15:26:07
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20160625052015AAafT1J