who can solve this x4-144=0?

Do you mean x^4 (x to the fourth power) or 4x (4 times x)? This is not clear? If you mean x^4,then:
x^4-144=0
(x^2-12)(x^2+12)=0
x^2=12 or x^2=-12
x = +/-2√3 or x = +/-2i√3

If you meant 4x, then:
4x-144 =0
4x = 144
x = 36

x⁴ - 144 = 0
(x²)² - 12² = 0
(x² - 12)(x² + 12) = 0
x² = 12 or x² = -12
x = √12 or x = -√12 or x = √(-12) or x = -√(-12)
x = 2√3 or x = -2√3 or x = (2√3)i or x = -(2√3)i

x⁴ - 144 = 0
(x²)² - 12² = 0 {a² - b² = (a-b)(a+b)}
(x² - 12)(x² + 12) = 0 {x²=-12 has no Real solutions - back to that later}
(x² - (2√3)²)(x² + 12) = 0
(x - 2√3)(x + 2√3)(x² + 12) = 0
Real solutions: x=2√3, x=-2√3

(x - 2√3)(x + 2√3)(x² - (i2√3)²) = 0 {as i²=-1, multiplying a value by -i² is the same as multiplying by 1}
(x - 2√3)(x + 2√3)(x - i2√3)(x + i2√3) = 0
Complex solutions: x = 2√3 + 0 i, x = -2√3 + 0 i, x = 0 + 2√3 i, x = 0 - 2√3 i

I like x = 36

x^4 - 144 = 0

x^4 = 144

x^2 = 12

x = 2\/3 OR - 2\/3 ANSWER

x={±2√(3), ±2i√(3)}
x^4-144=0 has 4 solutions, since 4 is it's highest power. Two real, and two complex.

X4-144=0
X=144/4
x=36 Answer

x^4 - 144 = 0

x^4 = 144

or, x^2 = 12

or, x = 2\/3 OR - 2\/3
Both of the above can be the answer.

Assuming x4 is x^4

x^4 = 144
x = 3.46

36

36

x4-144=0
x4=144
x=144/4
x=36 it is right answer.

36

since a2 - b2 = ( a+ b ) ( a- b ) in the same fomula if we put a = x2 and b = 12 so that b2 = 12^2 = 144 , then the equation x2 - 144 = 0 becomes ; ( x2 + 12 ) ( x2 - 12 ) = 0 , and therefore we get x2 = + or- 12 , so x = =+ or - !2 ^1/2 = + or - ( 4x 3 )^1/2 = + or - 2 * 3!/2 = + or - 3.4642

36

Assuming x4 means 4×x,
4x-144=0
Add 144 to both sides
4x=144
Divide 4 from both sides
X=36

x^4 - 144 = 0
(x^2 + 12)(x^2 - 12) = 0
Real solutions:
x = -2√3
x = 2√3
Complex solutions:
x = -2 i√3
x = 2 i √3

x^4 - 144 = 0
(x^2 + 12)(x^2 - 12) = 0
x^2 = -12 or x^2 = 12
x = 2i√3 or x = -2i√3 or x = 2√3 or x = -2√3

x^4 - 144 = 0, ie., (x^2 + 12)(x^2 - 12) = 0. Then x^2 = 12..(i) or x^2 = - 12..(ii). For (i) holding,
x = (+/-)2rt3. For (ii) holding, x = (+/-)2irt3.

x^4-144=0
add 144 to both sides
x^4 = 144
x = (144)^(1/4)
log(x) = log((144)^(1/4))
log(x) = (1/4) log(144)
log(x) = 0.5396
x = 10^(0.5396)
x = 3.4642

x^4 = 144
x^2 = 12 or x^2 = -12 <-- results in imaginary numbers, which I'm assuming you are expected to ignore
x = sqrt (12) = 2 x sqrt (3) or - sqrt(12) = -2 x sqrt(3)

(X-12)^2(x+12)^2=0

X=12 x=-12

x4 - 144 (+144) = 0 (+144)
x4 = 144
x4/4 = 144/4
x = 36

1+1