who can solve this x4-144=0?
回答 (23)
2016-06-29 8:24 am
Do you mean x^4 (x to the fourth power) or 4x (4 times x)? This is not clear? If you mean x^4,then:
x^4-144=0
(x^2-12)(x^2+12)=0
x^2=12 or x^2=-12
x = +/-2√3 or x = +/-2i√3
If you meant 4x, then:
4x-144 =0
4x = 144
x = 36
x^4-144=0
(x^2-12)(x^2+12)=0
x^2=12 or x^2=-12
x = +/-2√3 or x = +/-2i√3
If you meant 4x, then:
4x-144 =0
4x = 144
x = 36
2016-06-25 12:41 pm
x⁴ - 144 = 0
(x²)² - 12² = 0
(x² - 12)(x² + 12) = 0
x² = 12 or x² = -12
x = √12 or x = -√12 or x = √(-12) or x = -√(-12)
x = 2√3 or x = -2√3 or x = (2√3)i or x = -(2√3)i
(x²)² - 12² = 0
(x² - 12)(x² + 12) = 0
x² = 12 or x² = -12
x = √12 or x = -√12 or x = √(-12) or x = -√(-12)
x = 2√3 or x = -2√3 or x = (2√3)i or x = -(2√3)i
2016-07-04 10:16 pm
x⁴ - 144 = 0
(x²)² - 12² = 0 {a² - b² = (a-b)(a+b)}
(x² - 12)(x² + 12) = 0 {x²=-12 has no Real solutions - back to that later}
(x² - (2√3)²)(x² + 12) = 0
(x - 2√3)(x + 2√3)(x² + 12) = 0
Real solutions: x=2√3, x=-2√3
(x - 2√3)(x + 2√3)(x² - (i2√3)²) = 0 {as i²=-1, multiplying a value by -i² is the same as multiplying by 1}
(x - 2√3)(x + 2√3)(x - i2√3)(x + i2√3) = 0
Complex solutions: x = 2√3 + 0 i, x = -2√3 + 0 i, x = 0 + 2√3 i, x = 0 - 2√3 i
(x²)² - 12² = 0 {a² - b² = (a-b)(a+b)}
(x² - 12)(x² + 12) = 0 {x²=-12 has no Real solutions - back to that later}
(x² - (2√3)²)(x² + 12) = 0
(x - 2√3)(x + 2√3)(x² + 12) = 0
Real solutions: x=2√3, x=-2√3
(x - 2√3)(x + 2√3)(x² - (i2√3)²) = 0 {as i²=-1, multiplying a value by -i² is the same as multiplying by 1}
(x - 2√3)(x + 2√3)(x - i2√3)(x + i2√3) = 0
Complex solutions: x = 2√3 + 0 i, x = -2√3 + 0 i, x = 0 + 2√3 i, x = 0 - 2√3 i
2016-06-29 7:24 am
I like x = 36
2016-06-26 2:31 am
x^4 - 144 = 0
x^4 = 144
x^2 = 12
x = 2\/3 OR - 2\/3 ANSWER
x^4 = 144
x^2 = 12
x = 2\/3 OR - 2\/3 ANSWER
2016-07-05 9:52 pm
x={±2√(3), ±2i√(3)}
x^4-144=0 has 4 solutions, since 4 is it's highest power. Two real, and two complex.
x^4-144=0 has 4 solutions, since 4 is it's highest power. Two real, and two complex.
2016-07-05 2:30 pm
X4-144=0
X=144/4
x=36 Answer
X=144/4
x=36 Answer
2016-07-05 6:09 am
x^4 - 144 = 0
x^4 = 144
or, x^2 = 12
or, x = 2\/3 OR - 2\/3
Both of the above can be the answer.
x^4 = 144
or, x^2 = 12
or, x = 2\/3 OR - 2\/3
Both of the above can be the answer.
2016-07-03 12:11 pm
Assuming x4 is x^4
x^4 = 144
x = 3.46
x^4 = 144
x = 3.46
2016-07-03 10:59 am
36
2016-06-30 7:40 pm
36
2016-06-30 4:38 pm
x4-144=0
x4=144
x=144/4
x=36 it is right answer.
x4=144
x=144/4
x=36 it is right answer.
2016-06-29 8:54 pm
36
2016-06-29 9:53 am
since a2 - b2 = ( a+ b ) ( a- b ) in the same fomula if we put a = x2 and b = 12 so that b2 = 12^2 = 144 , then the equation x2 - 144 = 0 becomes ; ( x2 + 12 ) ( x2 - 12 ) = 0 , and therefore we get x2 = + or- 12 , so x = =+ or - !2 ^1/2 = + or - ( 4x 3 )^1/2 = + or - 2 * 3!/2 = + or - 3.4642
2016-06-26 12:40 pm
36
Assuming x4 means 4×x,
4x-144=0
Add 144 to both sides
4x=144
Divide 4 from both sides
X=36
Assuming x4 means 4×x,
4x-144=0
Add 144 to both sides
4x=144
Divide 4 from both sides
X=36
2016-06-25 1:34 pm
x^4 - 144 = 0
(x^2 + 12)(x^2 - 12) = 0
Real solutions:
x = -2√3
x = 2√3
Complex solutions:
x = -2 i√3
x = 2 i √3
(x^2 + 12)(x^2 - 12) = 0
Real solutions:
x = -2√3
x = 2√3
Complex solutions:
x = -2 i√3
x = 2 i √3
2016-06-25 1:18 pm
x^4 - 144 = 0
(x^2 + 12)(x^2 - 12) = 0
x^2 = -12 or x^2 = 12
x = 2i√3 or x = -2i√3 or x = 2√3 or x = -2√3
(x^2 + 12)(x^2 - 12) = 0
x^2 = -12 or x^2 = 12
x = 2i√3 or x = -2i√3 or x = 2√3 or x = -2√3
2016-06-25 1:11 pm
x^4 - 144 = 0, ie., (x^2 + 12)(x^2 - 12) = 0. Then x^2 = 12..(i) or x^2 = - 12..(ii). For (i) holding,
x = (+/-)2rt3. For (ii) holding, x = (+/-)2irt3.
x = (+/-)2rt3. For (ii) holding, x = (+/-)2irt3.
2016-06-25 12:31 pm
x^4-144=0
add 144 to both sides
x^4 = 144
x = (144)^(1/4)
log(x) = log((144)^(1/4))
log(x) = (1/4) log(144)
log(x) = 0.5396
x = 10^(0.5396)
x = 3.4642
add 144 to both sides
x^4 = 144
x = (144)^(1/4)
log(x) = log((144)^(1/4))
log(x) = (1/4) log(144)
log(x) = 0.5396
x = 10^(0.5396)
x = 3.4642
2016-06-25 12:28 pm
x^4 = 144
x^2 = 12 or x^2 = -12 <-- results in imaginary numbers, which I'm assuming you are expected to ignore
x = sqrt (12) = 2 x sqrt (3) or - sqrt(12) = -2 x sqrt(3)
x^2 = 12 or x^2 = -12 <-- results in imaginary numbers, which I'm assuming you are expected to ignore
x = sqrt (12) = 2 x sqrt (3) or - sqrt(12) = -2 x sqrt(3)
2016-06-25 1:06 pm
(X-12)^2(x+12)^2=0
X=12 x=-12
X=12 x=-12
2016-06-25 12:29 pm
x4 - 144 (+144) = 0 (+144)
x4 = 144
x4/4 = 144/4
x = 36
x4 = 144
x4/4 = 144/4
x = 36
2016-06-27 3:18 pm
1+1
收錄日期: 2021-04-18 15:24:25
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