An object of mass 0.56 kg is attached to a horizontal spring, with spring constant 50.0 N/m.?
2016-06-24 2:48 pm
An object of mass 0.56 kg is attached to a horizontal spring, with spring constant 50.0 N/m. If the object is stretched 5.50 cm from the equilibrium position and released, what is its maximum speed?
回答 (1)
2016-06-24 2:57 pm
✔ 最佳答案
Maximum K.E. of the object = P.E. stored in spring(1/2) m v² = (1/2) k (Δx)²
v = √[k (Δx)² / m]
Maximum speed, v = √(50.0 × (5.50/100)² / 0.56) m/s = 0.52 m/s
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