Let F(x)=x^2-x-y and G(x)=2x+8 Find G(6) and f(g(6)).?
回答 (4)
2016-06-24 2:50 pm
f(x) = x² - x - y (where y should be a constant)
g(x) = 2x + 8
g(6)
= 2*6 + 6
= 20
f(g(6))
= f(20)
= 20² - 20 - y
= 380 - y
g(x) = 2x + 8
g(6)
= 2*6 + 6
= 20
f(g(6))
= f(20)
= 20² - 20 - y
= 380 - y
2016-06-24 2:48 pm
f(x) = x² - x - y
g(x) = 2x + 8
g(6) = 2(6) + 8 = 20
f(g(6)) - f(20) = (20)² - 20 - y = 380 - y
g(x) = 2x + 8
g(6) = 2(6) + 8 = 20
f(g(6)) - f(20) = (20)² - 20 - y = 380 - y
2016-06-24 3:16 pm
Find G(6):
G(6) = 2(6) + 8
G(6) = 20
Now we can find F(G(6)), note that y in this function is just a constant otherwise it would be a function of x and y or F(x, y):
F(20) = 20^2 - 20 - y
F(20) = 380 - y
G(6) = 2(6) + 8
G(6) = 20
Now we can find F(G(6)), note that y in this function is just a constant otherwise it would be a function of x and y or F(x, y):
F(20) = 20^2 - 20 - y
F(20) = 380 - y
2016-06-24 2:50 pm
G(6) = 2(6)+8 = 20
F ( G(x) ) = F ( 2x+8) = (2x+8)^2 -(2x+8) - y
= (4x^2+32x+64) -2x-8 -y
= 4x^2 +30x +56 -y
F(G(6)) = 4(6)^2 +30(6)+56 - y
= 144 +180 +56 - y
= 380 - y
F ( G(x) ) = F ( 2x+8) = (2x+8)^2 -(2x+8) - y
= (4x^2+32x+64) -2x-8 -y
= 4x^2 +30x +56 -y
F(G(6)) = 4(6)^2 +30(6)+56 - y
= 144 +180 +56 - y
= 380 - y
收錄日期: 2021-04-18 15:11:08
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https://hk.answers.yahoo.com/question/index?qid=20160624064614AAbnjoR