a) Implicitly differentiate tan(x^7* t^6) with respect to x, given that dt/dx = v.?
回答 (3)
A)
d[tan(x⁷t⁶)] / dx
= {d[tan(x⁷t⁶)] / d(x⁷t⁶)} • [d(x⁷t⁶)/dx]
= sec²(x⁷t⁶) • [x⁷ (dt⁶/dx) + t⁶ (dx⁷/dx)]
= sec²(x⁷t⁶) • [x⁷ (6 t⁵) (dt/dx) + t⁶ (7x⁶)]
= sec²(x⁷t⁶) • (6x⁷t⁵v + 7x⁶t⁶)
= x⁶t⁵ (6xv + 7t) sec²(x⁷t⁶)
d/dx ( tan (x^7 t^6) ) = sec^2 (x^7 * t*6) ( 7x^6 t^6 + x^7 * 6t^5 dt/dx)
= sec^2 (x^7 * t*6) ( 7x^6 t^6 + x^7 * 6 * t^5 v)
= sec^2 (x^7 * t*6) ( 7x^6 t^6 + 6 x^7 t^5 v)
How bout I kick your *** for being lame asf
收錄日期: 2021-04-18 15:12:30
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20160624063509AAwTiKJ
檢視 Wayback Machine 備份