∫ cos[sin(????)] cos(????) ?????????
回答 (2)
2016-06-22 9:50 pm
Let u = sin(θ)
Then du = cos(θ) dθ
∫cos[sin(θ)] cos(θ) dθ
= ∫cos[sin(θ)] [cos(θ) dθ]
= ∫cos(u) du
= sin(u) + C
= sin[sin(θ)] + C
Then du = cos(θ) dθ
∫cos[sin(θ)] cos(θ) dθ
= ∫cos[sin(θ)] [cos(θ) dθ]
= ∫cos(u) du
= sin(u) + C
= sin[sin(θ)] + C
2016-06-22 9:46 pm
sin[sin(????)]+C
收錄日期: 2021-04-18 15:10:40
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20160622134500AAU3sZ8