Decomposition of potassium chlorate (KClO3) produces potassium chloride (KCl) and pure oxygen (O2). The balanced equation for the reaction is as follows.
2KClO3(s) => 2KCl(s)+3O2(g)
What volume of oxygen gas is released at STP if 10.0 g of potassium chlorate is decomposed? (The molar mass of KClO3 is 122.55 g/mol.)
0.914 L
1.83 L
2.74 L
3.66 L
Decomposition of potassium chlorate (KClO3) produces potassium chloride (KCl) and pure oxygen (O2).?
2016-06-22 9:35 pm
回答 (1)
2016-06-22 10:02 pm
✔ 最佳答案
2KClO₃ → 2KCl + 3O₂OR: Mole ratio KClO₃ : O₂ = 2 : 3
No. of moles of KClO₃ = (10.0 g) / (122.55 g/mol) = 0.0816 mol
No. of moles of O₂ released = 0.0816 × (3/2) = 0.1224 mol
Molar mass of gas at STP = 22.4 L/mol
Volume of O₂ released = (22.4 L/mol) × (0.1224 mol) = 2.74 L
The answer is : 2.74 L
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