f(x)=2x+4 and g(x)=3x-7 then find g^-1(2)?
回答 (2)
2016-06-22 9:02 pm
y = g(x) = 3x - 7
3x = y + 7
x = (y + 7)/3
Hence, g⁻¹(x) = (x + 7)/3
g⁻¹(2) = (2 + 7)/3
g⁻¹(2) = 3
3x = y + 7
x = (y + 7)/3
Hence, g⁻¹(x) = (x + 7)/3
g⁻¹(2) = (2 + 7)/3
g⁻¹(2) = 3
2016-06-22 9:01 pm
g = 3x - 7
The inverse is:
x = 3g - 7
x + 7 = 3g
g = (x + 7) / 3
The inverse of g at 2 is (2 + 7) / 3 = 9/3 = 3
The inverse is:
x = 3g - 7
x + 7 = 3g
g = (x + 7) / 3
The inverse of g at 2 is (2 + 7) / 3 = 9/3 = 3
收錄日期: 2021-04-18 15:09:52
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